HI Sparkfun folks, can you explain in more detail about how the I/O voltage switch works? I guess the processor still works with 3.3V digital inputs OK? Also, the schematic on the product page seems to be for a previous revision.
THanks!
So, I’ve notified internal teams that the schematic is slightly out of date. The schematic currently available does show the I/O selection option but at trace jumpers and not a switch, like the newest BlackBoard has now. However, the principle is exactly the same. The I/O pins work based off of the supplied VCC. If we switch to 3.3V then the IC will operate at 3.3V instead of 5V.
Thank you for pointing this out, and I hope this explanation helps clarify the issue.