Can the logic be running at 3.3v and the LCD at 5v? The power inputs are separated. VDD is logic supply and VO is LCD supply (and yet another pair for the back light but that’s outside the scope of my question).
Thanks Lyncon but I am confused; the data sheet doesn’t say just that but rather max LCD is VDD-VO = VDD+0.3v so let’s say VDD is 5 and VDD-VO=4.5 at 25C as the sheet says then simple math would reveal that VO=5-4.5=0.5 so the max contrast would be .5+.3=0.8v no? That would be less than a volt for the LCD driver?
ds18s20:
Thanks Lyncon but I am confused; the data sheet doesn’t say just that but rather max LCD is VDD-VO = VDD+0.3v so let’s say VDD is 5 and VDD-VO=4.5 at 25C as the sheet says then simple math would reveal that VO=5-4.5=0.5 so the max contrast would be .5+.3=0.8v no? That would be less than a volt for the LCD driver?
Vdd-Vo isn’t math: it’s a symbol. Regardless of that, even if it was math, don’t attempt to apply logic to Absolute Maximum Ratings: they know things about the device internals that they may not discuss.