Xbee with its battery

Hi

I didn’t find yet a way to use a single Xbee (without arduino) with its battery.

I thought about a liPo Battery 3.7V but it seems too much. this liPo sold on sparkfun are very handy and can be loaded with there charger.

It’s too bad that i can’t use it for my project where the place for the electronic part is very small.

Is this regulator (http://www.sparkfun.com/products/526 ) can deal with a lipo BAttery 3.7V and output a 3.3V ?

I don’t find the minimum Input Voltage.

Do you guys have any idea on how to use a single Xbee with a battery ?

thanks

Looking at the datasheet for the LD1117V33 (http://www.sparkfun.com/datasheets/Comp … 117V33.pdf) on page 6 it lists the dropout voltage of the regulator under a load 500mA at about 1.05v. The XBee Series 2 manual under “Specifications” lists a regular, non-PRO S2 module needing a minimum voltage of 3.0v and an S2B module needing a minimum voltage of 2.7v.

If you buy the LiPro battery you are interested in and wire it to the regulator you’ve identified with a few filtering caps (as shown in the regulator datasheet) and using the decoupling caps shown in the XBee manual (1uF and 8.2pF capacitors located to as near pin 1 as possible) I’m certain you’ll be able to run the XBee radio for quite awhile provided you set the sleep modes of the XBee appropriately.

What are you building? What sort of I/O will you be exchanging?

HI

thank you

Here is my project.

On one side : simple interrupt + Xbee + battery

Other side : Xbee + Arduino (to trig sounds)

Maybe i should use the Xbee explorer regulated, http://www.sparkfun.com/products/9132

What do you think about it ?

As long as you use a regular, non-PRO radio I believe that is a good choice!

On the Explorer, the diode (D1) in series with the data line is ever a problem due to very marginal logic 0 conditions. Seems like SFE should have corrected this design deficiency long ago.

Much better off to simply use two resistors in a voltage divider arrangement.