Help with circuit that shunts power to connected load

Hello.

https://lh3.googleusercontent.com/d990c … 68=s512-no

It’s been a while since I did any real circuit design… I am trying to plan out a circuit by which I have a load (LED A) and the lines going to and from it divert to some open leads.

If I were to connect a device that had another load (LED B) and mating connectors, the current would completely divert to B without a physical switch.

The diagram is simplified (obviously)… but all required electronics to ensure proper voltage etc is supplied to either of the loads is already handled on a logic board. I just want to sort of tap into the wires going to the load and create this plug-in overriding LED, basically.

Thanks.

The diagram is simplified (obviously)

Why post nonsense?

If you want circuit design suggestions, post the complete preliminary design.

Despite your not noting any current limiting resistors for LED protection, connecting another LED will not ‘divert’ the voltage/current from the ‘LED A’ unless you use some sort of circuit - I personally would use a headphone jack that disconnects the speakers and substitutes the headphone circuit.

just google ‘headphone jack socket’

DanV:
Despite your not noting any current limiting resistors for LED protection, connecting another LED will not ‘divert’ the voltage/current from the ‘LED A’ unless you use some sort of circuit - I personally would use a headphone jack that disconnects the speakers and substitutes the headphone circuit.

just google ‘headphone jack socket’

Nice. Elegant solution. Thank you. All the limiting resistors are on a logic board. I wanted to hijack the current going from the control board to the existing LED (via wires) to divert it to another LED. This’ll work.

@Dan, I had no complete preliminary design. I needed an initial advice to even see a direction for which to march.