In the layout below is there a way to convince Eagle that two nets are connected by way of an intraboard connection? I understand there are ways to avoid needing this connection so the example is a bit contrived but I am curious if there is an answer.
Your question isn’t clear. If there are 2 different nets [sic] , then, by definition they are NOT connected. Keep in mind that PCB’s don’t have nets - only schematics do.
PCB’s have traces, planes, copper pours and plated holes. Every geometrical shape of copper that connects to another copper shape, directly or indirectly, implements a single schematic net. In other words, all copper shapes that are interconnected are part of the same net. If 2 shapes are not connected in some way then they are separate nets/signals. You can’t have it both ways at the same time.
Sorry, I should have been more clear. The two highlighted traces represent the same net but are physically separate. They will, however, be connected at the board level by a wire between each connector. Eagle obviously knows these traces are part of the same net but how do I convince it that they will actually be connected at the board level thus eliminating the air wire. I’m trying to ascertain if this is a possibility.