I have an RTK Express and am using SW Maps. The RTK Express (not SW Maps) gets the RTK data from mount point P776_RTCM3 at rtgpsout.unavco.org. SW Maps connects to the RTK Express using Bluetooth. I have not provided SW Maps a Geoid File.
When I record a point in SW Maps and download the Excel file, I get the following:
ID 233
Remarks road
Time 08/29/2023 13:31:48.000 EDT
Geometry POINT Z (-71.15969189 44.14395690 480.087)
Latitude 44.1439569
Longitude -71.15969189
Elevation 480.087
Ortho Height 513.999
Instrument Ht 2.038
Fix ID 4
Speed 0.005
Bearing 0
Horizontal Accuracy 0.024
Vertical Accuracy 0.039
Subtracting 480.087 (SW Maps Elevation) from 513.999 (SW Maps Ortho Height) yields 33.912 M. The Geoid12b for 44.1439569 lat, -71.15969189 lon is 27.054 M.
I am guessing that the Elevation of 480.087 M is the height above the ellipsoid?
I would have guessed that the Ortho Height of 513.999 M was the height above the ellipsoid, but this does not seem to make sense.
If I take 480.087 M and add 27.054 M (from https://geodesy.noaa.gov/), I get 507.141 M. Converting 507.141 M to feet is 1,663.848 feet.
Data from the New Hampshire site (https://granitview.unh.edu/ ) for the LiDAR derived 2 foot Hypsographic Contours has this point between 1,666 and 1,668 feet.
It seems that taking the SW Maps 480.087 M and adding the NOAA GEOID12B of 27.054 for this location gets me within about 3 vertical feet (1,663.848 vs the topo of ~1,667).
With all of that, I have two main questions.
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Where does the SW Maps Ortho Height of 513.999 come from and how is it derived?
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Why doesn’t using the Elevation from SW Maps, and adding the GEOID12B delta come closer than 3 vertical feet of the LiDAR derived 2 foot Hypsographic Contours?