I have the BOB-15100 USB-C breakout board that will be connected to a 2.0 USB-A port on a windows PC using a USB-A to USB-C cable. The output will go to a micro usb cable that has VCC, GND, D+, D-, and a bare copper wire . What should I do with the CC1 and CC2 pins in order to output 5V, GND, and allow data transmission through D+ and D-? Below are the schematics for this board.
I believe USB-C ↔ USB 2.0 negotiates down to 500mA anyhow, so you won’t need to do anything with the cc1/2 (because it would negotiate down to 500mA either way)…but you could connect cc1&2 if you want to signal the host that it’s a standard usb device
The bare copper wire is usually used a ground for the shielding/housing, you can usually just leave it unconnected (but if feeling froggy solder it to the housing)
Thank you for your reply. Are you saying to connect cc1 and cc2 together do I still need to have the 5.1k resistors between them and ground?