Hi, I am creating my own PCB which will use microcontroller to control LEDs. The whole system will have 500 LED ws2812b shining at about 15% of the power (and not all at once) powered by a Power Bank. The 5V voltage goes to the LEDs, and the 3.3V voltage regulator goes to the microcontroller. The question is, do I need an additional current divider for the attached diagram or something else that will properly divide the 3A coming from the battery? Will the electricity distribute itself properly as needed? I would like to make the most of the current to illuminate the LEDs.
The attached diagram includes only 2 x ws2812b LEDs for simplicity, USB 3.1 plug and AMS1117 voltage regulator. Any comments on the simplification of the scheme are welcome 
You won’t need any sort of current divider at all, the current will just go where it’s needed automatically.
TS-Chris:
You won’t need any sort of current divider at all, the current will just go where it’s needed automatically.
Thanks, I wasn’t sure
One more question. All LEDs will be connected to 5V power supply but DIN from microcontroller will have only 3.3V. Should I use step-up level shifter for DIN to match 5V?
Most LEDs will probably be fine with the 3.3 volt data but if you have trouble, you could always use a logic level converter like [BOB-12009 to change that 3.3 volt data to 5 volts.](https://www.sparkfun.com/products/12009)
Thank you TS-Chris
While it will be a custom PCB I will probably use 74AHCT125. Maybe there is any simpler/better IC for this purpose?
That will probably work just fine, another possibility is the 74HC4050 if you happen to have any of those laying around.
